Sale!

Code Generation for an LC-3 Compiler

$30.00

ECE220: Computer Systems and Programming
Machine Problem 11
Code Generation for an LC-3 Compiler
This assignment requires you to use recursion to translate a description of a program in a subset of the
C language into LC-3 assembly code. Developing such code provides you with experience with the use of
recursion and pointer-based data structures in C, both of which are important tools. You will also gain
a better understanding of the methods and challenges involved in automating translations from one form
of program to another. Most of the compiler will be provided to you, including both code that translates
C code into an abstract syntax tree (AST) as well as C library routines to support basic arithmetic and I/O
on LC-3. Your focus will be on turning an AST into a sequence of LC-3 instructions.

Category:
5/5 - (2 votes)

ECE220: Computer Systems and Programming
Machine Problem 11
Code Generation for an LC-3 Compiler
This assignment requires you to use recursion to translate a description of a program in a subset of the
C language into LC-3 assembly code. Developing such code provides you with experience with the use of
recursion and pointer-based data structures in C, both of which are important tools. You will also gain
a better understanding of the methods and challenges involved in automating translations from one form
of program to another. Most of the compiler will be provided to you, including both code that translates
C code into an abstract syntax tree (AST) as well as C library routines to support basic arithmetic and I/O
on LC-3. Your focus will be on turning an AST into a sequence of LC-3 instructions.
Please read this document in its entirety before you begin to program.
On Reading the Code
You are not expected to read the more than 3,300 lines of C, lexer, parser, and LC-3 code
provided to you. You are welcome to do so, of course, but you do not need to read them to complete
this assignment. All relevant material from headers, etc., is included in this document. Furthermore, you
should be aware that a substantial amount of code (around 4,500 lines!) is automatically generated when
you build your compiler, and none of the automatically generated code (such as ece220 lex.yy.c) is meant
to be human-readable. Don’t try. If you want to remove the automatically-generated files so that you can
see what was there in the original distribution, type make clear.
A Subset of C
To simplify your task, the compiler supports only a narrow subset of the full C programming language.
Support is included for if statements, for loops, return statements, and expressions using most of the
C operators. Compound statements are required as opposed to simply being good practice. For example:
int i;
for (i = 0; 10 > i; i++) /* This code will generate a syntax error. */
printf (“%d\n”, i);
for (i = 0; 10 > i; i++) { /* To avoid, include braces around loop body. */
printf (“%d\n”, i);
}
Programs written for this compiler can declare global variables as well as a single subroutine (int main (),
of course). Local variables can be declared within main, but variable declarations are not otherwise allowed
(for example, within compound statements). Only two types are supported: int’s and one-dimensional
arrays of integers. Pointer types are not supported, and you can use arrays only with bracketed expressions
for indices. For example:
int a[1];
scanf (“%d”, a); /* NOT legal–will generate a syntax error */
scanf (“%d”, &a[0]); /* legal */
Constant strings can be used, but only as arguments to function calls, as shown by the format strings in the
printf and scanf examples above.
1
Most C operators are supported, including assignment (=), basic arithmetic (+, -, *, /, %, and negation),
pre- and post-increment and decrement (++, –), logical operators (!, &&, ||), and comparisons (<, <=, ==,
>=, >, !=). Taking the address of a variable or array element is also possible (as is necessary for scanf), but
almost no type checking is done for you.
Thus the compiler accepts the code below (as does gcc, but accompanied by warnings):
int i;
int j;
i = &j;
printf (“%d\n”, “Hello!\n”);
printf (“i at %d, j at %d\n”, &i, &j);
scanf (“%d”, i);
The output produced by the printf calls in the code above is unpredictable and of little value, but the
scanf call passes the value of variable i instead of its address and thus could change memory unpredictably.
In the code above, i was set previously to the address of j, but such tricks are confusing and error-prone.
Examples of other missing functionality include pointer dereferencing, multi-dimensional arrays, structures,
enumerations, defining new types, variable initialization within a declaration, loops other than for loops,
switch statements, and bitwise operations. Anything not explicitly mentioned as a type of AST node in
the AST section of this document is simply not included in the language, and you need not worry about
implementing it. Of course, you won’t be able to use such functionality in C programs on which you want
to use your compiler, either.
Code Generation
Your code must generate LC-3 assembly for the main subroutine and print it to stdout. As you know,
a C function such as main consists of variable declarations and statements. Variable declarations will be
translated for you into a symbol table that your code must use when generating assembly code for each of the
statements. The stack frame will already be set up for you, and will be torn down when your code finishes.
Be sure to execute the stack frame teardown—do not insert RET instructions directly into the code that
you generate.
This machine problem is not intended to require substantial LC-3 programming on your part. Each of
the recursive components that you write should be no more complex than implementing a single step of
systematic decomposition, and you may in fact want to review the LC-3 implementation of the conditional
and iterative decompositions that we covered early in the course.
In addition to statements, much of the work involved in code generation involves computing the results of
expressions. To simplify your task, you are required to use the stack to compute all expressions. As you may
recall, any expression can be computed using a stack and some basic rules. To “execute” a literal operand
such as a number is seen, push the operand onto the stack. To “execute” an operator, pop operands for the
operator from the stack, apply the operator to those operands, and then push the operation result back onto
the stack.
2
Although the LC-3 code generated by this approach will be lengthy and inefficient, use of a stack combines
nicely with recursion to allow a straightforward implementation of most of this MP. For example, the code
for an addition operator (AST220 OP ADD, as described later) performs the following sequence of operations:
generate code to produce the first operand of the add (recursive call)
generate code to produce the second operand of the add (recursive call)
pop the second operand from the stack (print LC-3 instructions)
pop the first operand from the stack (print LC-3 instructions)
add the two together (print an ADD instruction)
push the result onto the stack (print LC-3 instructions)
The LC-3 instructions that you produce must be aware of the LC-3 register conventions as well as any
assumptions that you make in code that can call it recursively. Consider, for example, what might happen
if we did not use a stack-based approach for expressions: a given binary operator might produce its first
operand and put it into R0, then generate code to produce its second operand. However, the code needed
for the second operand must avoid overwriting the first operand in R0. What if the same operator is used
by the second operand, though (for example, 1+(2+3))? Use of a stack avoids such complexity.
The register conventions for LC-3 are as follows:
R0-R3 available for your code’s use
R4 global data pointer
R5 main’s stack frame pointer
R6 stack pointer
R7 used by JSR/JSRR
Note also that the assembly routines provided for you do change certain register values when they are called
(details are in the next section).
The C Library
In order to avoid your having to implement functionality in LC-3, we have written and provided you with
a small library of functions to support you when generating the assembly code. The library includes four
interfaces that can be used directly from C and another three interfaces intended for your use in implementing
basic arithmetic. The calls visible in C are as follows:
int printf (const char* format, …); /* assembly label PRINTF */
int rand (); /* assembly label RAND */
int scanf (const char* format, …); /* assembly label SCANF */
void srand (int new seed); /* assembly label SRAND */
These calls have C-style interfaces: arguments must be put onto the stack in the correct order, and the
return value will be on the stack. Except for R6 (decremented to store the return value) and R7 (changed
by JSR), no register values are changed by these subroutines. As described in class, the caller is responsible
for removing arguments from the stack after the call to any of these functions returns.
The printf and scanf routines work in the standard way, but support only a handful of escapes:
%d print/scan an argument as a decimal integer
%% print/scan a single % character
\n print/scan a line feed
\\ print/scan a single \ character
The printf routine returns the number of characters printed. The scanf routine returns the number of
integers converted. The rand routine returns a pseudo-random number between 0 and 215−1, and the srand
routine sets the seed for the pseudo-random number generator used by rand.
3
The arithmetic functions defined for you have register-based interfaces. All three are binary operations on
R0 and R1, and all three return the result of the operation in R0. Except for R0 (the return value) and R7
(changed by JSR), no register values are changed by these subroutines. The routines are as follows:
DIVIDE divide R0 by R1, round towards 0, and store the result in R0
MODULUS calculate R0 % R1 (C definition) and store the result in R0
MULTIPLY multiply R0 by R1 and store the result in R0
All seven of these library routines use the stack for storing callee-saved registers.
Abstract Syntax Trees
The abstract syntax tree (AST) is one form of intermediate representation used as interface between the
front-end and the back-end of a compiler. Recall that the front-end of a compiler translates from a high-level
language (such as C) into an intermediate representation, while the back-end translates the intermediate representation into assembly code. Your job in this assignment is to write an LC-3 back-end for an intermediate
representation based on ASTs.
An AST is a pointer-based data structure consisting of nodes that represent statements and expressions in
the original code. The structure used in your compiler is the following:
typedef struct ast220 t ast220 t;
struct ast220 t {
ast220 type t type; /* type of AST node */
int32 t value; /* a number (PUSH INT, DEBUG MARKER) */
char* name; /* a string (PUSH STR, VARIABLE) */
ast220 builtin func t fnum; /* function number (FUNC CALL) */
ast220 t* test; /* test condition (IF STMT, FOR STMT) */
ast220 t* left; /* left child/first operand */
ast220 t* middle; /* middle child (FOR STMT) */
ast220 t* right; /* right child/second operand */
ast220 t* next; /* next AST node */
};
The type field of an AST node (the ast220 t structure) specifies what kind of node is represented. For
example, one AST node might represent an if statement, while a second node represents a variable reference,
and a third node represents an addition operation. In general, the type of the AST node determines
the meaning (or lack thereof) of the structure’s other fields. The exception to this rule is the next
field, which is used to link together AST nodes representing sequential statements in a block of code as well
as sequential arguments in a function call.
4
Two general classes of AST nodes are defined for your compiler: statements and expressions. The subset
of C supported by the compiler is minimal, thus only five statement types are possible:
AST220 FOR STMT a for statement
test test condition
left initialization expression (an AST220 POP STACK node, or NULL)
middle loop body (statements linked by next)
right update expression (an AST220 POP STACK node, or NULL)
AST220 IF STMT an if statement
test test condition
left then code block (statements linked by next)
right else code block (statements linked by next)
AST220 RETURN STMT a return statement (don’t forget to branch to the stack frame teardown code
provided to you)
left expression to be returned
AST220 POP STACK an expression, with result discarded (for example, a=b;)
left expression to produce and then pop (discard)
AST220 DEBUG MARKER a debugging marker
value marker value
Fields not defined in the table above have no meaning and should not be assumed to hold any particular
value (for example, NULL). The only statement type that might not be immediately clear to you from your
experience with C is the AST220 DEBUG MARKER, which is simply a debugging aid designed to help you with
your coding. If you add a statement of the form DEBUG(20); to your C program, an AST node of type
AST220 DEBUG MARKER will appear in its place (with value equal to 20), which in turn enables generation of
an assembly comment marking that point in the assembly output (using a routine already written for you).
Expression nodes include all operators supported by our subset of C as well as nodes for integer and string
constants, variable references, and so on. The simplest expressions include constants, variable references,
and function calls, for which AST types are shown in the table below. In general, the code generated (recursively) for an expression AST node should leave the result of the expression on top of the stack.
AST220 PUSH INT an integer constant
value the number itself (fits into 16-bit 2’s complement)
AST220 PUSH STR a string constant
name the string, including quotation marks
AST220 VARIABLE a variable reference
name variable name (look up in symbol table)
left array index expression (for array variables; NULL for scalar variables)
AST220 FUNC CALL a function call; be sure to pop off arguments, but leave the return value on top of stack
fnum C library function identifier; one of:
AST220 PRINTF
AST220 RAND
AST220 SCANF
AST220 SRAND
left argument list (expressions from right to left linked by next)
The AST220 VARIABLE node is special in the sense that it is used both for expressions that use the value
as well as the address of the variable. In a general expression, you should assume that the value of the
variable must be found and pushed onto the stack. The address of the variable plays a role whenever the
AST220 VARIABLE node is the child of one of the types in the table at the top of the next page. In these
cases, you should process the variable directly and not treat it as a general expression (that is, do not recurse
to your routine for generating the code for an arbitrary expression).
5
AST220 GET ADDRESS the address of a variable
left the variable, an AST220 VARIABLE node; note that array variables
will also have an expression for the array index
AST220 OP ASSIGN an assignment; copy the expression into the variable, but do not pop the
expression result off of the stack
left the variable, an AST220 VARIABLE node
right the expression
AST220 OP PRE INCR pre- and post-increment and decrement
AST220 OP PRE DECR left the variable, an AST220 VARIABLE node
AST220 OP POST INCR
AST220 OP POST DECR
The remaining AST nodes correspond to unary and binary operators for arithmetic, logical operations, and
comparisons. Remember that assembly code subroutines for multiplication, division, and modulus are provided for you.
AST220 OP NEGATE negate an expression
left the operand (an expression)
AST220 OP ADD binary arithmetic operations
AST220 OP SUB left the first operand (an expression)
AST220 OP MULT right the second operand (an expression)
AST220 OP DIV
AST220 OP MOD
AST220 OP LOG NOT logical NOT; result is 0 or 1
left the operand (an expression)
AST220 OP LOG AND binary logic operations; result is 0 or 1; don’t forget to perform shortcutting
AST220 OP LOG OR left the first operand (an expression)
right the second operand (an expression)
AST220 CMP NE comparison/relation operations; result is 0 or 1
AST220 CMP LESS left the variable, an AST220 VARIABLE node
AST220 CMP LE right the expression
AST220 CMP EQ
AST220 CMP GE
AST220 CMP GREATER
Implementation of LC-3 code generation for comparisons is provided to you as a building block. The implementation provided makes the following simplifying assumption: for the purpose of all comparisons,
the resulting code ignores 2’s complement overflow. As you know, the LC-3 ISA supports comparisons only with 0. Thus it is natural to transform comparisons by subtracting the right side from the left
side and comparing the result with 0. This approach does not work when the representation overflows.
For example, is A < B true when A = 0x4000 and B = 0x8000? Clearly not: B is negative! On the other
hand, A − B = 0x4000 − 0x8000 = 0xC000 < 0, which is true.
6
The Symbol Table
A symbol table will be constructed and provided for you. As described previously, AST nodes of type
AST220 VARIABLE use the name field to specify the variable name referenced. In the case of an array variable,
the node’s left field will hold an expression to calculate the array index. The parser checks that an index
expression is always present for an array variable and is never present for a scalar (non-array) variable. Two
symbol table routines are of interest to you:
void symtab dump ();
symtab entry t* symtab lookup (const char* vname);
The symtab dump routine is called for you to place a human-readable copy of the symbol table into the
assembly code output, but you can call it again if you find it convenient to make additional copies. However,
these extra copies should be removed before you turn in your code.
The symtab lookup routine finds the symbol table entry associated with a given variable name. We disallow
variable shadowing (using the same name for both a local and a global variable). The symbol table entry is
defined as follows:
typedef struct symtab entry t symtab entry t;
struct symtab entry t {
char* name; /* variable name (case sensitive) */
int array len; /* size of array (0 = not an array) */
int is global; /* global variable (1) or local to main (0) */
int offset; /* offset with respect to appropriate register */
};
When you generate LC-3 instructions to operate on a variable, you must use the is global and offset
fields of the variable’s symbol table entry to locate it. As you may recall from class and/or the text, global
variables are relative to R4, the global data pointer, and local variables are relative to R5, main’s frame
pointer.
You may assume that the symbol table offsets for all variables fall in the range [−16, 15]. Large
arrays may extend beyond this interval, but the first element of any array will always fall within it when we
test your MP.
Unique Labels
A facility for creating and using unique labels in the assembly code that you generate is provided for you:
ece220 label t* label create ();
char* label value (ece220 label t* label);
When you need a label, declare a variable of type ece220 label t* and obtain a new label by calling
label create. To print the label, call label value to obtain a string representation from the label pointer.
7
Getting Started
After reading this document completely, go into your mp11 directory and type make to compile everything
into an executable called c220. At this point, the c220 compiler will produce valid assembly output from a
valid C program, but the assembly code implementation of the main subroutine will not actually do anything
other than stack frame setup and teardown.
Your code goes into the mp11.c file. Specifically, you must fill in the function
void MP11 generate code (ast220 t* prog);
Note that you may not modify any files other than mp11.c. We will not use any other files from you in
testing your code.
Existing Code Generation
Some of the work needed to generate code has been done for you, and the mp11.c file provided to you already
contains a significant amount of the necessary structure. What’s there is about 700 lines, most of which is
prototypes and comments.
Code optimization is not a goal for this assignment, and thus any reasonably-sized piece of C code is
likely to break the limits on LC-3 branch and JSR offsets. To avoid assembler failures, you may only use
the branch instruction when you know that the branch offset is in range, and you must always use JSRR
rather than JSR. For the branches, a routine to print an appropriate instruction sequence for a “branch”
with arbitrary offset (that is, a JMP instruction) is provided to you:
void gen long branch (br type t type, ece220 label t* label);
Branch types are defined near the start of the mp11.c file.
Also included in mp11.c are a couple of big switch statements to direct recursive calls for generic statements
(gen statement) and expressions (gen expression). These switch statements direct each type of AST node
to a small function to generate the code for that type of node. You will have to write the code for most of
these smaller functions, but some (the six comparison operations) have been provided for you as an example.
The debug marker function is also included.
First Half
You must complete all tasks in both halves by the deadline. The separation is meant to only to guide you
in how to approach the problem. We suggest that you do so in the order listed here, which will allow you to
check your progress.
• MP11 generate code: Start by writing the main entry point for your code. Until you’ve written this
function, none of the other functions in mp11.c will be called. The ast argument is a linked list of
AST nodes (linked by the next field) representing the statements in the C program’s main function.
All you have to do for now is generate code for each one.
• integer constants: Next, write code to push a constant integer on to the stack. Here, you’ll need to
play the same trick as you’ll see in the long branch code provided to you. That is, put the .FILL with
the constant into the code, then branch around it. Ugly, but this approach guarantees that your LD
instruction has a valid offset.
8
• return statement: Implement the return statement. The stack frame is already set up for you, so
you can just look up the relative offset in the book or your notes. Keep in mind that you’ll need to
branch to the stack teardown after you’ve set the return value. Add code to MP11 generate code to
put the label in the right place, and keep track of the label in a file-scope variable.
Once you have reached this point, you can compile, assemble, and simulate a program consisting of a
return statement. The code that calls main also prints the return value; try it out and make sure that
your code works so far.
• negation: Negation is one of the simplest operations. Take the value off the top of the stack, negate it,
and put it back. To test, return -(42);—the parentheses are necessary; try it without them to see
why.
• addition and subtraction: Two more fairly simple stack operations are next. Addition and subtraction
take two values, perform the appropriate operation, and push the result back onto the stack. Be sure
to get the order right for subtraction. You can test by using the return statement, for example, return
10+(40-8);.
• string constants: Handle string constants in the same way that you handled integer constants. Remember that the address of the first character of the string should be pushed.
• function calls: Function calls will take a bit of work. First, note that the arguments are given to you
as they appear from right to left in the C code. Once you’ve pushed them all, use a JSRR (again, see
the long branch code provided) to call the library, then clean up the arguments, copying the return
value to be the only thing that you leave on the stack.
Now you can try the classic first C program: printf (“Hello, world!\n”);
• scalar variable reference: Write the code to read a scalar variable and push it onto the stack. You’ll
need to look the variable up in the symbol table to know where to find it. For now, you may assume
that the variable is not an array (or get a headstart on the second checkpoint by handling both kinds).
• scalar variable assignment: Now write the code to handle an assignment to a scalar variable. Again,
for now you may assume that you don’t need to handle assignments to array elements.
• pop stack statement: A C expression followed by a semicolon is a statement (which is not as useless as
it may sound, since “a=10” is an expression). The expression leaves a value on the stack, which must
be discarded to finish the statement. All you need to do is pop the stack.
Once you have completed these tasks, your compiler will be able to handle assignments and return statements using expressions involving addition, subtraction, negation, and scalar variables. You can also print
out results using calls to printf. Try a few different programs to check that things work properly.
Second Half
You must also complete the following tasks, although we suggest that you get the first half working before
undertaking these tasks.
• multiplication, division, and modulus: Start with a few more binary operators. For these, rather than
implementing the operations yourself, simply call (using JSRR) to the C library provided to you.
• array variable reference: Now go back to your variable reference code and handle accesses to array
variables. Remember that the offset in the symbol table is to the start of the array, so you’ll need to
add in whatever index is provided in the C code (it’s an expression that must be evaluated).
9
• array variable assignment: Again, go back to your assignment code and handle assignments to array
variables.
If you haven’t already done so, try compiling some code that uses your new operators as well as arrays
to check that you are generating code correctly. Be sure to try both local and global variables.
• increment and decrement: These operators come in four varieties and require you to read a variable
(possibly an array entry), modify it, write it back, and return a result on the stack. Be careful and
test them all before moving on.
• for stmt: If you don’t remember how the for loop works, you may want to look it up in the book or
your notes. Note that the initialization and update AST nodes are statements in our compiler so that
you don’t have to pop the results from the stack in gen for statement. The test condition is a regular
expression, since you’ll have to test it after producing it. The body is a linked list of statements. Put
them all in the right order, remember that anything non-zero is true in C, and use long branches in
case the loop body is long.
• get variable address: For the scanf call, you’ll need to be able to pass variable addresses. Write the
function that finds the address of a variable, be it a scalar or an array element, and pushes it onto the
stack.
• if statement: As with the for statement, you may want to look up the LC-3 implementation of the
conditional decomposition before implementing this statement. The test is an expression, and the then
and else blocks are linked lists of statements, either of which may be empty (but you don’t need to
optimize your code in such cases).
• logical operations: The logical NOT, OR, and AND operations are somewhat more complicated than
the operators that you have implemented already. First, they always result in 0 or 1, and you will
have to make sure that you generate code to place the right value on the stack. Next, both OR and
AND require shortcutting, which means that the second expression is only evaluated if the first allows
it to change the outcome of the logical operation. For example, if the first operand of OR is true, the
second operand is not evaluated.
10
Grading
Details to be determined, but roughly 85% on functionality, and 15% on comments and documentation. Any
warnings generated by compilation of your code will result in the same deduction (10%).
Note that the rules are largely the same as with previous MPs. All of your code must be contained within
the mp11.c file in the mp/mp11 subdirectory of your repository. We will NOT grade files with any other
names.
As always, your functions must be able to be called many times and produce the correct results, so we
suggest that you avoid using any static storage (or you may lose most/all of your functionality points).
Executing the Compiler
If you are working within the VM, you must make sure that the parser compiler—a tool called Bison—has
been installed. To do so, type
sudo apt install bison
The compiler, c220, then accepts code as input from the keyboard and outputs assembly language to the
display. To override this behavior, for example to read a program, compile it, and produce a file with assembly code, type (for example) the following:
cat tests/testprog.c | ./c220 > testprog.asm
You can then inspect the testprog.asm file—be sure to look only between the “STUDENT CODE” labels,
as the rest is automatically-generated library code. Or you can assemble it with lc3as and execute it with
lc3sim.
You can write your own simple C programs and run them through the compiler, too. Only a subset of C is
supported, but have fun!
11

Open chat
Need help?
Hello
Can we help you?