Machine Learning Homework 3


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COMS 4771: Machine Learning
Homework 3
Note: In your write-up please only provide the specific information requested. In particular,
no code need be submitted.
This homework will use the same data sets that you used in the last homework, from the file
spam.mat which can be found on Canvas or the course webpage. Loading this file into MATLAB will
generate two matrices: train spam, the training set, with 3601 labeled examples, and test spam,
the test set, with 1000 labeled examples. Each example represents an email with 57 features and a
binary label indicating whether the email is spam (label = 1) or not (label = 0). A description of the
data can be found at with detailed descriptions of the features at
spambase/spambase.names. The rows of the data set found there have been randomly permuted
to generate the train and test sets.
In this homework, you will experiment with AdaBoost using decision stumps as the base learner.
Decision stumps are extremely simple classifiers which use a single feature and a threshold to make
their prediction: in other words, they’re depth 1 binary decision trees. To train a decision stump,
we compute, for each feature i, and for each threshold value θ among the values of feature i, the
cost of the decision rule which splits the training set using into two parts (examples with xi θ,
and examples with xi ≤ θ) and using the majority label as a prediction in each part. The cost is
simply the number of mistakes made by this decision rule (this corresponds to classification error
as the measure of uncertainty: don’t worry about Gini index and entropy in this homework). To
use decision stumps in AdaBoost, we need to generalize this training method to allow weights on
Part 1 of assignment: (weightage: 1%.) Give pseudocode for training a decision stump
when traininig examples are given weights. Use the same tie-breaking rules as the last homework:
in case there are two features xi and xj that both yield minimum cost decision stumps, break the
tie by choosing the lower indexed one (i.e. i if i < j). Also, if for any leaf, the costs of predicting
1 and 0 are the same, break the tie in favor of the 0 label.
Next, implement your pseudocode in MATLAB. Using this code, write a MATLAB function
function params = hw3 train adaboost(train data, num rounds)
where the integer parameter num rounds is the number of rounds of AdaBoost to run on the training
set train data, using your decision stump training code as the weak learner in each round. The
output params is any convenient MATLAB data structure to represent the ensemble of decision stumps
(and their weights) computed by AdaBoost.
Write another function which computes predictions for test data given the parameters computed
by the hw2 train adaboost function, and error rate1 made on the test data, with the following
function loss = hw3 test adaboost(params, test data)
Part 2 of assignment: (weightage: 3%.) Run AdaBoost using hw3 train adaboost with
train data = train spam and num rounds = 1, 2, . . . , 100. For every value of num rounds, compute the training error by using hw3 test adaboost on test data = train spam, as well as the
test error by using hw3 test adaboost on test data = test spam. Plot curves (on a single graph)
of the training error and test error on the y-axis with the number of rounds on the x-axis, and
include the graph in your homework submission. Also report a few specific values of the training
and test errors in a table with the following format:
num rounds training error rate test error rate
Although it is not required for this homework, you may wish to compare the numbers you get
using AdaBoost with decision stumps with the numbers you got for training decision trees in the
last homework. To do a fair comparison, a complete decision tree of depth d has 2d
leaf nodes,
each of which can be thought of as a decision stump, so compare such a decision tree to a classifier
constructed by AdaBoost running for 2d
Hint: Since AdaBoost constructs the ensemble incrementally, the output param computed by
running AdaBoost for 100 rounds can also be used to reconstruct the output of AdaBoost for any
fewer number of rounds.
Part 3 of assignment: (weightage: 2%.) Polynomial regression is a technique for solving
regression problems by fitting a bounded degree polynomials to the data rather than a linear
function, as in ordinary least squares. The simplest case is when examples are represented a single
scalar feature x ∈ R. The class of regression functions, Fd, is the set of all polynomial functions of
x with degree bounded by d, where d is a parameter. Thus, the class can be defined as
Fd = {c0 + c1x + c2x
2 + . . . cdx
| c0, c1, . . . , cd ∈ R}.
Suppose we use squared loss to measure goodness of fit, i.e. for an example (x, y), if the prediction
yˆ, then the loss is (y − yˆ)
. So the polynomial regression problem is to find the polynomial f ∈ Fd
which minimizes training error on some training set {(x1, y1),(x2, y2), . . . ,(xn, yn)}, i.e.
arg min
(y − f(x))2
1Error rate is the fraction of mistakes, i.e #mistakes
#examples .
Give a closed form formula for solving the polynomial regression problem, ignoring any numerical
Extra credit: (weightage: 2%.) We have informally argued that the AdaBoost algorithm
uses the weighting mechanism to force the weak learner to focus on the problematic examples in the
next iteration. In this question we will find some rigorous justification for this argument. Compute
the value of
Dt+1(x, y) · yft(x).
Here, the notation is the same as used in the lecture slides: ft
is the classifier found by AdaBoost in
round t, and Dt+1 is the distribution computed from Dt using ft
. Based on the value you computed,
what can you say about how good of a classifier ft
is when examples are drawn from Dt+1?
Extra credit: (weightage: 1%.) In your experiments, you may have noticed something
curious about the error rates (either training or test error) when you run AdaBoost for 1 round or
2 rounds. Explain why this happens.

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