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Workshops 3 & 4 Geometrical shapes

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JAC444
Workshops 3 & 4
Description:
This assignment lets you practice basic concepts such as encapsulation and abstraction,
inheritance, polymorphism, and exceptions.
In this assignment, you will be working with geometrical shapes such as: Circle, Square,
Rectangle, Parallelogram, and Triangle. Use the following figure as a reference
(you do not need to calculate shapes’ area for this assignment):
Figure1 – Shape objects needed for this workshop.
You will need to create geometrical shapes and calculate their perimeters. Therefore, you must
develop java classes for all the geometrical shapes mentioned above (put all your classes in a
package named shapes). Each class must be able to calculate the shape’s perimeter. For each
class, you must provide implementations for toString(), at least one constructor,
setters/getters, and the documentation for the entire class.
You should also provide an interface Shape as the root of the inheritance hierarchy and design
the appropriate “is-a” relationships among the above-mentioned classes.
A text file named shapes.txt has been given to you. The file contains the definitions of some
geometrical shapes. Each line might define a geometrical shape with the following format:
name,x,y,z. The name is the shape’s name and x,y,z are the values needed to define the shape’s
dimensions. The empty line signals the end of the file.
If a line is not properly formatted or it does not contain the necessary number of values to
correctly describe a shape, your program must ignore that line. If you cannot build the
geometrical shapes with the given values (ex. zero or negative values for dimensions, wrong
values for three sides of a triangle, etc.), you should throw an exception. Therefore, there is a
need to define some custom Exception classes for some of your classes. Your program must be
capable of storing all the geometrical shapes read from the file in one data structure. Since arrays
are the only data structure that we have covered so far, you must use just one array to contain all
JAC444 Summer – 2022 2
06/06/2022 Workshops 3 & 4 Page 2 of 5
the shapes in this assignment. In the future, while we cover collections in Java, you will figure
out that other data structures could ease your programming tasks a lot!
Copy the shapes.txt file in the root folder of your Java project in Eclipse. We would cover
exceptions in week 6 and File IO in week 7, but if you want to start ahead of time, you could use
the following code snippet to read all the lines from the file. You could also consider using the
split() method of class String to split each line to its composing items:
try (BufferedReader br = new BufferedReader(new FileReader(fileName))) {
while ((s = br.readLine()) != null) {
String[] tokens = s.split(“,”);
//your code
}
} catch (IOException e) {
System.out.println(e.getMessage());
}
Do the following tasks in different modules (methods) of the Main class of your project:
Task 1: Read the file Shapes.txt, create the shapes and store them in your data structure. Then
print the number of shapes you created, and finally, print all the shapes and their calculated
perimeters polymorphically. For the sample input file, sample output could be:
——->JAC 444 Assignment 1<——-
——->Task 1 … <——-
Invalid radius!
Invalid side(s)!
Invalid side!
Invalid side(s)!
32 shapes were created:
Circle {r=1.0} perimeter = 6.28319
Circle {r=2.111} perimeter = 13.2638
Circle {r=1.1} perimeter = 6.91150
Triangle {s1=3.0, s2=4.0, s3=5.0} perimeter = 12.0000
Triangle {s1=3.9, s2=4.0, s3=5.9} perimeter = 13.8000
Square {s=3.0} perimeter = 12.0000
Parallelogram {w=4.0, h=9.0} perimeter = 26.0000
Rectangle {w=3.0, h=5.1} perimeter = 16.2000
Square {s=5.0} perimeter = 20.0000
Parallelogram {w=3.9, h=9.2} perimeter = 26.2000
Triangle {s1=4.9, s2=5.0, s3=8.9} perimeter = 18.8000
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06/06/2022 Workshops 3 & 4 Page 3 of 5
Rectangle {w=8.0, h=2.1} perimeter = 20.2000
Circle {r=3.8} perimeter = 23.8761
Parallelogram {w=3.1, h=9.8} perimeter = 25.8000
Triangle {s1=3.1, s2=4.1, s3=5.1} perimeter = 12.3000
Parallelogram {w=0.1, h=0.2} perimeter = 0.600000
Triangle {s1=4.0, s2=5.0, s3=6.0} perimeter = 15.0000
Rectangle {w=3.1, h=5.2} perimeter = 16.6000
Circle {r=10.0} perimeter = 62.8319
Square {s=0.1} perimeter = 0.400000
Triangle {s1=3.1, s2=4.0, s3=5.0} perimeter = 12.1000
Circle {r=2.0} perimeter = 12.5664
Parallelogram {w=3.9, h=9.3} perimeter = 26.4000
Parallelogram {w=1.1, h=1.2} perimeter = 4.60000
Rectangle {w=3.0, h=5.2} perimeter = 16.4000
Square {s=100.1} perimeter = 400.400
Square {s=100.2} perimeter = 400.800
Circle {r=10.1} perimeter = 63.4602
Triangle {s1=3.0, s2=4.0, s3=5.0} perimeter = 12.0000
Triangle {s1=3.9, s2=4.8, s3=5.7} perimeter = 14.4000
Parallelogram {w=1.2, h=2.1} perimeter = 6.60000
Square {s=1.0E-5} perimeter = 4.00000e-05
Task 2: Delete the triangle with the minimum perimeter (there could be more than one
minimum) and the circle with the maximum perimeter (there could be more than one maximum)
from the shapes. Print the all the remaining shapes and their perimeters polymorphically. For the
sample input file, sample output could be:
——->Task 2 … <——-
Circle {r=1.0} perimeter = 6.28319
Circle {r=2.111} perimeter = 13.2638
Circle {r=1.1} perimeter = 6.91150
Triangle {s1=3.9, s2=4.0, s3=5.9} perimeter = 13.8000
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06/06/2022 Workshops 3 & 4 Page 4 of 5
Square {s=3.0} perimeter = 12.0000
Parallelogram {w=4.0, h=9.0} perimeter = 26.0000
Rectangle {w=3.0, h=5.1} perimeter = 16.2000
Square {s=5.0} perimeter = 20.0000
Parallelogram {w=3.9, h=9.2} perimeter = 26.2000
Triangle {s1=4.9, s2=5.0, s3=8.9} perimeter = 18.8000
Rectangle {w=8.0, h=2.1} perimeter = 20.2000
Circle {r=3.8} perimeter = 23.8761
Parallelogram {w=3.1, h=9.8} perimeter = 25.8000
Triangle {s1=3.1, s2=4.1, s3=5.1} perimeter = 12.3000
Parallelogram {w=0.1, h=0.2} perimeter = 0.600000
Triangle {s1=4.0, s2=5.0, s3=6.0} perimeter = 15.0000
Rectangle {w=3.1, h=5.2} perimeter = 16.6000
Circle {r=10.0} perimeter = 62.8319
Square {s=0.1} perimeter = 0.400000
Triangle {s1=3.1, s2=4.0, s3=5.0} perimeter = 12.1000
Circle {r=2.0} perimeter = 12.5664
Parallelogram {w=3.9, h=9.3} perimeter = 26.4000
Parallelogram {w=1.1, h=1.2} perimeter = 4.60000
Rectangle {w=3.0, h=5.2} perimeter = 16.4000
Square {s=100.1} perimeter = 400.400
Square {s=100.2} perimeter = 400.800
Triangle {s1=3.9, s2=4.8, s3=5.7} perimeter = 14.4000
Parallelogram {w=1.2, h=2.1} perimeter = 6.60000
Square {s=1.0E-5} perimeter = 4.00000e-05
Task 3: Calculate and print the total perimeter of all parallelograms and the total perimeter of all
triangles. For the sample input file, sample output could be:
——->Task 3 … <——-
Total perimeter of Parallelogram is: 116.19999999999999
Total perimeter of Triangle is: 86.4
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Marking Criteria and Tasks:
Please note that you should:
a- have an appropriate indentation.
b- have proper file structures and modularization.
c- follow Java naming conventions.
d- document all the classes properly.
e- not have debug/useless code and/or file(s) left in assignment.
f- have good intra and/or inter-class designs.
in your code!
• Workshop 3 – Developing and running the desired solution for task 1 (Building, storing,
calculating, and printing all the geometrical shapes, correctly): 5 marks.
• Workshop 4 – Developing the features and running the desired solutions (for tasks 2 and
3, correctly): 5 marks.
• Note that you should submit your source code – just individual .java files and
screenshots which demonstrate the way your code runs.)
Deliverables and Important Notes:
• You are supposed to submit your solutions online on BB by the end of the day on
Tuesday, 14
th of June 2022 for Workshop 3 and by the end of the day on
Tuesday, 21st of February 2022 for Workshop 4.)
• Please note that you would be allowed to submit just once, so please be super
careful and double-check before you hit submit.
• There would be a 20% penalty for each day (or part of it,) in case you submit
late!
• Remember that you are encouraged to talk to each other, the instructor, or to anyone
else about any of the assignments, but the final solution may not be copied from
any sources.

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